RE: [PHP] finding a variables name

Hello. you can try passing the name of the variable? i.e.: function makeJSArray($array_name) { global $$array_name $array = $$array_name; ... ... } otherwise, I don't think you can logically access the name. Consider this: $a=array(...); $b = &a; makeJSArray( $b ); What name will you get, 'a' or 'b' ? Regards, Eetay -----Original Message----- From: Joseph Blythe [mailto:joe.blythe@binarylogic.com.au] Sent: Tuesday, May 15, 2001 6:45 AM To: php-general@lists.php.net Cc: php-general@lists.php.net Subject: Re: [PHP] finding a variables name Joseph Blythe wrote: > Ok here is what I am trying to acheive, basically turning a php array > into a javascript array, note this is untested and most likley won't > work :-) > > Where $array_name I need the same name as the functions first and only > argument $array, so I need the name of the array that has been passed > to the function. > > /////////////////////////////////////////////////// > > function makeJSArray($array) { > > $out = "$array_name = new Array("; > > $size = sizeof($array); > $i = 0; > while ( list($key, $val) = each($array) ) { > > $out .= "$array_name[$key] = $val"; > > if ($size != $i - 1) > $out .= ","; > } > > $out .= ");"; > return $out; > } > > ///////////////////////////////////////////////// > > Thanks, > > Joseph He he, would also help if I closed my while loop and added the increment for $i -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net