Re: If (!$submit)
| From: | bill | Date: | Thu, 17 May 2001 14:02:24 +0000 |
| Subject: | Re: If (!$submit) | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-53237@lists.php.net to get a copy of this message | ||
Two suggestions:
Use
if (!isset($submit))
OR
change the order around
<?php
if ($submit)
{
// Results of login form, including login failed or successful print()
}
else
{
// First html page containing login form
}
?>
kind regards,
bill hollett
Tarrant Costelloe wrote:
> When using:
>
> <?php if (!$submit)
> {
> // First html page containing login form
> }
> else
> {
> // Results of login form, including login failed or successful print()
> }
> >?
>
> I get an error on line one, due to it at first not recognising the variable
> $submit. If I ignore this and continue to fill in the form, on the clicking
> the submit button I am then delivered to the same page of which it shows the
> results.
>
> So the only problem being, is when you first go to the page you get:
>
> Warning: Undefined variable: submit in C:\Documents and Settings\Tarrant
> Costelloe\Desktop\locahost\default.php on line 1
>
> then the form, on which being filled in and submitted brings you back to the
> page without the message and a print() of whether login successful or not.
> How do I get rid of the original error?
>
> Tarrant Costelloe
> Web Developer
> InsurE-com Ltd.
> ------------------------------------
> Office Tel: +44 (0)1273 852014
> Mobile: +44 07714087114
> tcostelloe@insur-e.net
> http://www.insur-e.net
>
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