Re: Finding if a number is in the range
| From: | Zak Greant | Date: | Fri, 18 May 2001 03:35:18 +0000 |
| Subject: | Re: Finding if a number is in the range | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-53380@lists.php.net to get a copy of this message | ||
Or just use a simple chain of if statements :)
if ($num >= 200 && $num <= 299) {
echo "$num is between 200 and 299";
} else if ($num >=1000 && $num <= 2263) {
echo "$num is between 1000 and 2263";
} else if ($num >=2264 && $num <= 2499) {
echo "$num is between 2264 and 2499";
} else {
echo "$num is not between 200 and 299,
1000 and 2263 or 2264 and 2499";
}
If you have a large number of these to do,
you could store your upper and lower bounds
in an array and use a loop to process the
bounds.
ie.
// set up our bounds
$bounds = array (
-10, -1,
0, 199,
200, 299,
1000, 2263,
2264, 2499
);
// make sure that we have a matched sets of bounds
// the bounds array should have at least 2 elements
// and the remainer (modulus) of $count / 2 should be 0
$count = count ($bounds);
$count > 1 AND 0 === ($count % 2)
OR die ('The $bounds array must contain one or more matched
elements.');
for ($index = 0; $index < $count; $index += 2) {
if ($number >= $bounds[$index] && $number <= $bounds[$index + 1]) {
$between = sprintf ("%s is between %s and %s.",
$number, $bounds[$index], $bounds[$index + 1]);
break;
}
}
if (isset ($between)) {
echo $between;
} else {
// join the bounds into a string separated by ..
$bounds = join ('..', $bounds);
// convert every second set of .. to <br>
$bounds = ereg_replace ('([^.]+\.\.[^.]+)\.\.', '\1<br>', $bounds);
echo "Number $number not found with any of the specified
ranges:<blockquote>$bounds</blockquote>";
}
--zak
----- Original Message -----
From: "MaD dUCK" <madduck@madduck.net>
To: "Joseph Blythe" <joe.blythe@binarylogic.com.au>
Cc: <php-general@lists.php.net>
Sent: Thursday, May 17, 2001 7:53 PM
Subject: Re: [PHP] Finding if a number is in the range
> also sprach Joseph Blythe (on Fri, 18 May 2001 11:12:23AM +0930):
> > How do I find if a number is in a range example:
>
> assuming that the ranges are continuous, make an array of the first
> number for each range and then implement a custom binary search for
> O(lg n) performance.
>
> martin; (greetings from the heart of the sun.)
> \____ echo mailto: !#^."<*>"|tr
> "<*> mailto:" net@madduck
> --
> "i wish there was a knob on the tv to turn up the intelligence.
> there's a knob called 'brightness', but it doesn't seem to work."
> -- gallagher
>
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