RE: [PHP] 'break' command question

This is the way it works in C. Perhaps the documentation shouldn't include the word "if". It really doesn't make any sense other way. > -----Original Message----- > From: Chris Gray [mailto:grayt@netrover.com] > Sent: Friday, July 07, 2000 8:37 AM > To: php-general@lists.php.net > Subject: [PHP] 'break' command question > > > There seems to be an inconsistency regarding 'IF' in the Break command > documentation. > > (From the manual) > break ends execution of the current if, for, while, or switch structure. > break accepts an optional numeric argument which tells it how many nested > enclosing structures are to be broken out of. > 1 > 2 $i = 0; > 3 while ($i < 10) { > 4 if ($arr[$i] == "stop") { > 5 break; /* You could also write 'break 1;' here. */ > 6 } > 7 $i++; > 8 } > 9 > > This 'break' really does break out of BOTH the IF and the WHILE > (I tested a > similar script) > <? > $i = 0; > while ($i < 10) { > if ($i == 5) { > break; /* You could also write 'break 1;' here. */ > } > $i++; > echo "$i<br>"; > } > ?> > > Using 'break 2' produces this error --- > Fatal error: Cannot break/continue 2 levels in > /home/httpd/html/ggg/break.php on line 5 > > > Please forgive my ignorance if there is some arcane Unix explanation for > this. > Or have I totally misunderstood the example? > > Chris >