RE: [PHP] All of a sudden I get Warning: Bad arguments to implod e() in busca_01.php on line 133

Try: ************************************************ if (!is_array($array_id)) { $string_id=$array_id; } else { $string_id= implode(":",$array_id); } ************************************************ You have to always make sure, you are passing Array into an implode() or explode(). BTW: your code would look cooler like this: $string_id = is_array($array_id) ? implode(":",$array_id) : $array_id; Sincerely, Maxim Maletsky Founder, Chief Developer PHPBeginner.com (Where PHP Begins) maxim@phpbeginner.com www.phpbeginner.com -----Original Message----- From: Martin Cabrera Diaubalick [mailto:martin@notodo.com] Sent: Tuesday, May 22, 2001 5:41 PM To: php-general@lists.php.net Subject: [PHP] All of a sudden I get Warning: Bad arguments to implode() in busca_01.php on line 133 Hello Everyone! This is my code ************************************************ if (count($array_id)==1) { $string_id=$array_id; } else { $string_id= implode(":",$array_id); } ************************************************ I've been testing it for three days and never had an error, now it comes and goes. Do you know what could be wrong? $array_id is an array of integers Thanks in advance -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net