Re: debugging and getting output from php code embedded in html
| From: | Ed Vul | Date: | Fri, 07 Jul 2000 18:03:39 +0000 |
| Subject: | Re: debugging and getting output from php code embedded in html | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-5428@lists.php.net to get a copy of this message | ||
I am also very green, maybe even teal... but i think i see your problem:
both echo commands are inside the if statement...
$conn = pg_Connect("host=localhost user=mcsauto dbname=mcsauto");
if (!$conn)
{
echo "Error !!!.\n";
}
echo "No Error !!!.\n";
I think that would work... but I may be wrong too....
and there might be some errors in your connect string, but i know nothing
about that :)
""James Purvins"" <purvinsj@voyager.net> wrote in message
news:015001bfe83b$1fc23900$28dbcfa9@net...
I am extremely green and just starting my php journey.
how do i display output information in an HTML file for debugging purposes?
currently, it seems all my "echo" commands in the html file do not display
when i browse the file. where are these echo commands going? are they going
to the great bit bucket in the sky??? how do i get them to display??
am i missing something really basic here?
here is the code fragment ---->
$conn = pg_Connect("host=localhost user=mcsauto dbname=mcsauto");
if (!$conn) { echo "Error !!!.\n"; echo "No Error !!!.\n" } ;
in either case...success or failure...shouldn't i be getting a message when
i browse the file?
thank you for your patience....this list is really great!!!
Jim Purvins