RE: [PHP] Missing arguments for function in class? (object-orientedprogramming)

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 > I have a function that works perfectly (from within a script). But > when I make it a class (object) and call it from an external file, > I get the following error: > > Warning: Missing argument 1 for display_records() in > http://www.friendshipcenter.com/Objects/display_records.inc > on > line 5 > > Warning: Missing argument 2 for display_records() in > http://www.friendshipcenter.com/Objects/display_records.inc > on > line 5 > > After the warnings, it executes the function without passing values > to the variables (i.e., it doesn't work), and then it executes the > function a second time perfectly (with the appropriate variables). > > Line 5 is this: > > function display_records($row, $record_count) > > It displays the first error message for $row, and the second error > message for $record_count. Because your function has the same name as your class whenever you create a new instance of the class the function will automatically run. So by creating a new class you are calling the function without passing any arguments. either a) rename the function or b) call the class like this $my_records = new Display_Records($row, $record_count); sorry for any wrong use of terminology HTH M@ -----BEGIN PGP SIGNATURE----- Version: PGPfreeware 7.0.3 for non-commercial use <http://www.pgp.com> iQA/AwUBOzrpgaW0/zC+QxWwEQLkWwCg+ZTT0Kwld191fqnfQMNRKUEk9FYAoM8X 9oD3Bf5U9eTiGo/mRPU/dEEX =rbZj -----END PGP SIGNATURE-----