RE: [PHP] PHP & ImageMagick

Did you try the escapeshellcmd () function ? - Russ --- Toolshed Computer Productions - Professional PHP Hosting Hosting - Dedicated Servers - Design - Programming http://www.toolshed51.com -----Original Message----- From: Jeffrey Barendse [mailto:barendse2@chello.nl] Sent: Thursday, June 28, 2001 8:01 AM To: php-general@lists.php.net Subject: [PHP] PHP & ImageMagick In PHP I try to run a shell command with the following source code: $fotonaam = 'convert -font arial -pointsize 20 -gravity center -fill white -draw "text 5,5 VERKOCHT" image.jpg image2.jpg'; exec($fotonaam); PHP runs the program but the -draw "text 5,5 VERKOCHT" is not executed (there is no VERKOCHT in the image2.jpg). I tried everything but I can't solve the problem. Could somebody explain to me how it's possible that the program (convert) runs but there (seams to be) a problem with -draw "text 5,5 VERKOCHT". If I run the same command troughs telnet/ssh as root or nobody it works fine Is it something with the " and the combinative with the exec function (I also tried \")? Or is it because I run PHP in safe mode and the convert program tries to run a external program what is not in the . path (you now, the basic safe mode restriction)? Please help me.. I'm getting despaired on this in. ;-) Regards, Jeffrey Barendse -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net