Re: chdir() help

I'm not sure I know exactly what you want, as the script isn't clear on its purpose. If you simply want to print out all the images in e:\work\image, and nothing else, the code would be much simpler. <? $dir = opendir("e:/work/image"); while ($file_name=readdir($dir)) { if ($file_name <> "." && $file_name <> "..") { echo "<img src='image/$file_name'>"; } } ?> /* Chris Lambert, CTO - chris@whitecrown.net WhiteCrown Networks - More Than White Hats Web Application Security - www.whitecrown.net */ ----- Original Message ----- From: McShen <hshen@crosswinds.net> To: <php-general@lists.php.net> Sent: Saturday, July 07, 2001 11:38 AM Subject: [PHP] chdir() help hi Currently, i am working in e:\work, and there is a folder named "image" under e:\work, so, the path to image is e:\work\image. I have a script under e:\work, and i wanna display all images under the folder e:\work\image, I use chdir() to change the directory. but it wouldn't work. it still displays the images under e:\work. Why is that? Does chdir() work under win2k pro? here is my script ------- <?php $dir_name = "e:\work"; $dir = opendir($dir_name); while ($file_name=readdir($dir)) { if (($file_name!="." && $file_name!="..")) { echo $file_name."\n&nbsp;&nbsp;"; if (chdir('e:\work\image')) { echo "current dir is e:\work\image"; } echo "<IMG SRC=$file_name>"; } } closedir($dir); ?> ----- Please help me to fix the problem. Thanks.