Re: require_once(); questions

Actually this does work: //First_File.php <? $test = "I am the test variable"; ?> //Second_File.php <? echo $test; ?> //Active file <? require "First_File.php"; require "Second_File.php"; ?> That would produce the output of : I am the test variable An include or require just places the files' contents at the line you include it. So after the includes(requires) my parsed code was: <? $test = "I am the test variable"; echo $test; ?> Hope this helps ----- Original Message ----- From: "Inércia Sensorial" <inerte@hotmail.com> To: <php-general@lists.php.net> Sent: Saturday, July 07, 2001 5:59 PM Subject: [PHP] require_once(); questions > Hi All, > > I have a function that includes files based on some SQL queries. On one of > the first loaded files, I want to define a function and use it on another > included file. Something like: > > includes file: > first_file.inc.php > This file has: $test = "Show me!"; > > Then include file: > second_file.php > This file has: echo $test; > > But doesn't show nothing, so I guess it is not possible to do. Am I right? > If so, what's the best alternative? > > Also, another question.... since it is a function that includes the files, > the contents of these files are not available outside the function scope.. > what's the best way to use it outside the function? > > Thanks a lot.... > > -- > > > Julio Nobrega. > > A hora está chegando: > http://sourceforge.net/projects/toca > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >