RE: [PHP] Average of column...
| From: | Jeff Lewis | Date: | Tue, 10 Jul 2001 15:54:11 +0000 |
| Subject: | RE: [PHP] Average of column... | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-57178@lists.php.net to get a copy of this message | ||
This doesn't work:
$age_result = mysql_query("select AVG(age) as avgage FROM bat_rost WHERE
ownerID = '$teamID'");
$row = mysql_fetch_object($age_result);
$age=$avgage;
echo "Average age - ".$teamID.$avgage;
Neither does this:
$age_result = mysql_query("select AVG(age) as avgage FROM bat_rost WHERE
ownerID = '$teamID'");
$res = mysql_fetch_row($age_result)
$age=$res[0];
echo "Average age - ".$teamID.$avgage;
> -----Original Message-----
> From: Remo Pini [mailto:remo.pini@pini.org]
> Sent: Tuesday, July 10, 2001 11:41 AM
> To: jeff@hyrum.net; php-general@lists.php.net
> Subject: RE: [PHP] Average of column...
>
>
> if you do a
>
> $res = mysql_fetch_row($age_result)
>
> $res[0] will be the value of AVG(age).
>
>
> > -----Original Message-----
> > From: Jeff Lewis [mailto:jeff@hyrum.net]
> > Sent: Tuesday, July 10, 2001 5:27 PM
> > To: php-general@lists.php.net
> > Subject: [PHP] Average of column...
> >
> >
> > I am trying to obtain the average age for a few teams in my database.
> >
> > Am using the below code:
> >
> > $age_result = mysql_query("select AVG(age) FROM bat_rost WHERE ownerID =
> > '$teamID'");
> > while(($row = mysql_fetch_object($age_result))){
> > $age=$row->age;
> > echo "Average age - ".$teamID.$age;}
> >
> > How can I get the average age from this?
> >
> > Jeff
> >
> >
> > --
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> >
> >
>
>