RE: [PHP] Get filename in php command line
| From: | Boget, Chris | Date: | Tue, 17 Jul 2001 16:14:51 +0000 |
| Subject: | RE: [PHP] Get filename in php command line | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-58291@lists.php.net to get a copy of this message | ||
> I had that before.
> OK, seems that my problem is not that simple. The thing is ,
> I have something
> like this in my file test.php:
> require('my_api.inc');
> echo "This is test.php3";
> Now, in my_api.inc, I want to know that I run test.php3, when I do
> bash$ php test.php3
> and the filename is test.php3 . __FILE__ will give my my_api.inc
> instead. I need it because my_api.inc do all sort of authenticating,
> session, etc.
__FILE__ will give you the name of the file that uses that constant.
So, based on the above, I believe that you are using __FILE__ only
in my_api.inc (which is pretty much what you said, I'm just looking
for verification).
What you can do instead is this:
in "my_api.inc", have the following code:
echo "Currently Running file is: ";
echo ( $CurrentRunningFile ) ? $CurrentRunningFile : __FILE__;
in test.php
<?
$CurrentRunningFile = __FILE__;
include( "my_api.inc" );
echo "This is test.php3<br>\n";
?>
Define "$CurrentRunningFile" on line one of all your files. Or
something along those lines...
Chris