Re: php- something that i don't understand

Yassel Omar Izquierdo Souchay pressed the little lettered thingies in this order... > Hey guys > here is my code > > 4: mysql_connect() or die ("Problemas conectandose a la base de datos"); 5: > $query="select * from info where FirstName='$FirstName' and 6: > LastName='$LastName' and email='$email'"; 7: $result = > mysql_db_query("users", $query); *8: $r=mysql_fetch_array($result); > ************ 9: $count=$r["count"]; > > and i follow redcieving this message > > Warning: Supplied argument is not a valid MySQL result resource in > c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 8 > > Change line 7 to this: $result = mysql_db_query("users", $query) or die(mysql_error()); What is the error after you do that? Christopher Ostmo a.k.a. tech@AppIdeas.com AppIdeas.com Innovative Application Ideas Meeting cutting edge dynamic web site needs since the dawn of Internet time (1995) Business Applications: http://www.AppIdeas.com/ Open Source Applications: http://open.AppIdeas.com/