Fw: [PHP] php- something that i don't understand
| From: | Jason Bell | Date: | Tue, 17 Jul 2001 19:48:21 +0000 |
| Subject: | Fw: [PHP] php- something that i don't understand | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-58325@lists.php.net to get a copy of this message | ||
Oops.. forgot to CC the group......
----- Original Message -----
From: "Jason Bell" <jbell@barkingrat.com>
To: "Yassel Omar Izquierdo Souchay" <yois@sics.transnet.cu>
Sent: Tuesday, July 17, 2001 12:42 PM
Subject: Re: [PHP] php- something that i don't understand
> try this:
>
> mysql_connect("YOUR_DB_HOST","DB_USERNAME","DB_PASSWORD");
> mysql_select_db("DB");
> $query = "select * from info where FirstName='$FirstName' and
> LastName='$LastName' and email='$email'";
> $result = mysql_query($query);
>
>
> ----- Original Message -----
> From: "Yassel Omar Izquierdo Souchay" <yois@sics.transnet.cu>
> To: <php-general@lists.php.net>
> Sent: Tuesday, July 17, 2001 1:37 PM
> Subject: [PHP] php- something that i don't understand
>
>
> Hey guys
> here is my code
>
> 4: mysql_connect() or die ("Problemas conectandose a la base de datos");
> 5: $query="select * from info where FirstName='$FirstName' and
> 6: LastName='$LastName' and email='$email'";
> 7: $result = mysql_db_query("users", $query);
> *8: $r=mysql_fetch_array($result); ************
> 9: $count=$r["count"];
>
> and i follow redcieving this message
>
> Warning: Supplied argument is not a valid MySQL result resource in
> c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 8
>
>
> thanks for your answers
> Yassel
>
>
>