Re: How make the time
| From: | elias | Date: | Wed, 18 Jul 2001 08:42:27 +0000 |
| Subject: | Re: How make the time | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-58407@lists.php.net to get a copy of this message | ||
select count(*) from test1
where
MINUTE(tm1) >= 15
and
MINUTE(tm1) <= 30
and
HOUR(tm1)=12
this query will return you on column containing how many record found in
that time range, same as how many customers where surfed at that time
where 30-15=interval
and 12 is the hour you're checking in!
"David Tandberg-Johansen" <david@datajo.no> wrote in message
news:20010717233605.94548.qmail@pb1.pair.com...
> Hello!
>
> I am trying to make an online booking script for a client (restaurant),
and
> I am using MySQL to store the booking information
> The restaurant have openings hour from 11:00 -> 01:00, but do only take
> reservation between 11:00->22:30.
> The client wants to get a report written out over each hour like this:
>
> 11:00 2 Customers
> 11:15 32 Customers
> 11:30 12 Customers
> ...
> ...
> 22:30 14 Customers
>
> In the MySQL table I have set up the time field as 'time' with 00:00:00 as
> default.
>
> Everything is ok, but I am stuck on how to make this report. The customer
> have set an interval of 15 mnutes between possible time to book, so I have
> to make an 'SELECT'-query based on when the restaurant opens to the time
of
> the last possible booking time. But how do I make the timeset (11:00:00
and
> up to 22:30:00)
>
> My far out example:
> interval = 15;
> while (time<=endtime){
> time=starttime
> DBCONNECTION
> Select * from booking wher tine_field='time'
> time = time+interval
> }
>
> Do anyone have any tips on how I can solve this
>
> David
>
>