Re: sql query successful

From: Date: Wed, 18 Jul 2001 19:42:38 +0000
Subject: Re: sql query successful
Groups: php.general 
Request: Send a blank email to php-general+get-58503@lists.php.net to get a copy of this message
Tyler Longren pressed the little lettered thingies in this order... > Hello everyone, > > I've been writing database enabled site for quite a while now. One thing I > have never figured out it how to determine if a sql query is successful. > > This works: > if ($connection = mysql_connect("host","username","password")) { > print "Successful connection": > } > else { > print "No connection"; > } > > But this won't work: > > if ($sql = mysql_query("SELECT * FROM table ORDER BY rand()")) { > print "SQL executed successfully."; > } > else { > print "SQL not executed successfully."; > } > > Can anyone tell me how I can tell if the SQL executed successfully? Is > there any method besides OR DIE? > What's wrong with "or die(..." ? If you get no error, the query was successful. If you take your "$sql =" out it *should* work. mysql_query returns TRUE or FALSE depending on whether or not the query succeeded. This isn't tested, but it should work: if (mysql_query("SELECT * FROM table ORDER BY rand()")) { echo "Success!"; } else { echo "Failure!"; } Your statement above is checking to see if the fact that $sql is equal to mysql_query("SELECT * FROM table ORDER BY rand()") is TRUE, but you're using an assignment operator (=) and not a comparison operator (==), so it should always return FALSE. (Can you use an assignment operator in an if() statement?) Christopher Ostmo a.k.a. tech@AppIdeas.com AppIdeas.com Innovative Application Ideas Meeting cutting edge dynamic web site needs since the dawn of Internet time (1995) Business Applications: http://www.AppIdeas.com/ Open Source Applications: http://open.AppIdeas.com/

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