Re: assigning a part of the name of a variable with another variable before php replaces it with the value

To answer your question: $postfld = $HTTP_POST_VARS[$fname[$i]]; should work. BTW, I just use something like: if ($client) { // or in your case: if (${$fname[$i]}) // code to be evaluated if $client exists and is not 0, not null/void/nil, and is not an empty string } J Matthew DeChant wrote: > Specifically, > > If I have 3 HTTP_POST_VARS: > > HTTP_POST_VARS["client"] = test1 > HTTP_POST_VARS["directory"]= test2 > HTTP_POST_VARS["password"] = > > and I don't know the names of the vars ahead of time, how would I run a > check to see if they exist and then get the specific POST_VARS's value. This > is what I've got so far: > > $squery = "select * from $db where "; > $qh = fw_query("select * from $db"); > $fields = odbc_num_fields($qh); > for ($i=1;$i<=$fields;$i++) { > # assign $fname the possible field names in the database > (client,directory,password) > $fname[$i] = odbc_field_name($qh,$i); > # assign $postfld the variable name, ie. $HTTP_POST_VARS["client"] > $postfld = $HTTP_POST_VARS["($fname[$i])"]; > # check that it exists and is not blank > if (isset($postfld) AND ($postfld != "")) { > $value[$i] = $postfld; > $squery.= "$fname[$i] like $value[$i] AND "; > } > } > # pop last AND > $squery= substr($squery, 0,-5); > > so how do you make this work: $postfld = $HTTP_POST_VARS["($fname[$i])"]; > > thanks, > > -m > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net