Re: How do I write a compound variable?

Arthur, Thank you very much for your help. I tried it and it works perfectly. I haven't tried the array yet though, I'm a bit shy of them as I don't know much about accessing arrays yet. Perhaps in the future. Thank you again. Hugh ----- Original Message ----- From: Arthur <x@apx.org> To: Hugh Danaher <hdanaher@earthlink.net> Sent: Monday, August 06, 2001 5:41 PM Subject: Re: [PHP] How do I write a compound variable? > To make your code work use curly braces for the compound variables. > > http://www.php.net/manual/en/language.variables.variable.php > > $high_1995=22; > $high_1996=23; > $high_1997=20; > $high_1998=18; > $high_1999=20; > $high_2000=21; > $high_2001=23; > > $low_1995=22; > $low_1996=23; > $low_1997=20; > $low_1998=18; > $low_1999=20; > $low_2000=21; > $low_2001=23; > > for ($year=1995;$year<=2001;$year++) > { > ${"avg_" . $year} = ( ${"high_" . $year} + ${"low_" . $year} > )/2; // create $avg_1995, ... > print "${"avg_" . $year}<br>"; > } > > > To do it without compound variables do this: > > $arr = array( > 1995 => array(high=>22,low=>22), > 1996 => array(high=>23,low=>23), > 1997 => array(high=>20,low=>20), > 1998 => array(high=>18,low=>18), > 1999 => array(high=>20,low=>20), > 2000 => array(high=>21,low=>21), > 2001 => array(high=>23,low=>24), > ); > > foreach($arr as $year=>$vals){ > $avg = ( $vals["high"] + $vals["low"] ) / 2; > echo $year . " - " . $vals["high"] . " - " . > $vals["low"] . " - " . $avg . > "<br>\n"; > } > > > > - Arthur >