Re: HELP!! QUERY_STRING

From: Date: Sat, 11 Aug 2001 05:17:37 +0000
Subject: Re: HELP!! QUERY_STRING
References: 1  Groups: php.general 
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I think this is what you're going for: $portNum = 5500; $arr = explode(":",$QUERY_STRING); $ipname = $arr[0]; if(isset($arr[1])) { $portNum = $arr[1]; }; On Friday 10 August 2001 19:00, you wrote: > the things i want it to do are: > when i go to index.php?172.0.0.1:5500 > that it would change the $ipname to 172.0.0.1 and > $portNum to 5500 > and if i go to > index.php?172.0.0.1 > then $ipname to 172.0.0.1 and > $portNum to 5500 > > so if i would go to: > index.php?255.255.255.255 > $ipname to 255.255.255.255 and > $portNum to 5500 > > ok.. i think i know 50% of the solution of this problem: > if $portNum eq'' > $portNum "5500"; > else > } > > is that right or i that cgi or is that totally wrong? > > right now this is my code: (index.php) > > > #################################### > > > <? > > #First output the HTML page > > ?> > <? > #Some functions > if (! $sock = fsockopen($ipname, $portNum, &$num, &$error, 5)) > print ("<IMG > SRC=\"http://hlpass.macomega.com/red.jpg\" WIDTH=10 > HEIGHT=10>"); > else{ > print ("<IMG > SRC=\"http://hlpass.macomega.com/green.jpg\" WIDTH=10 > HEIGHT=10>"); > fclose($sock); > } > #If the form has been posted, process the query, otherwise there's > #nothing to do yet > > if(!$queryType) > exit; > > #Make sure the target appears valid > > if( (!$ipname) || (!eregi("\.",$ipname)) ){ > message("Error: You did not specify a valid target host or IP."); > exit; > } > > #Figure out which tasks to perform, and do them > > if( ($queryType=="all") || ($queryType=="checkp") ) > checkp($ipname,$portNum); > > ?> > > ####################################

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