Re: Invalid directory resource

In article <000a01bfe912$c9c865a0$90c864ce@john>, terranlune@yahoo.com ("John Fuetsch") wrote: > I'm trying to open a directory and print out all files that have $id in = > the filename, but when I use the code below, I get "1 is not a Valid = > Resource" on the readdir line. The directory exists, and I think I'm = > calling it correctly. The weird thing is that it works about 15% of the = > time, but they rest it gives me this error. Any suggestions? Try giving the full pathname to $dir. > # Load Directory Into Array > > $dir =3D "images/thumbs"; > > $handle=3Dopendir($dir); > while ($file =3D readdir($handle)) { > > if(strstr($file,$id)) { > $images[count($images)] =3D $file; > } > > } > # Clean up and sort > closedir($handle); > sort($images); > > ------=_NextPart_000_0007_01BFE8D8.1B62C120-- > > > > __________________________________________________ > > Do You Yahoo!? > > Talk to your friends online with Yahoo! Messenger. > > http://im.yahoo.com -- Richard Lynch | If this was worth $$$ to you, buy a CD US Customer Support Director | from one of the artists listed here: Zend Technologies USA | http://www.L-I-E.com/artists.htm http://www.zend.com | (this has nothing to do with Zend, duh!)