Re: if statement and imageline()

What are you getting? An image at all? Broken image? Try getting rid of the header("image/jpeg") or whatever, and see if you have some error message. -- WARNING richard@zend.com address is an endangered species -- Use ceo@l-i-e.com Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic.com/volunteer.htm ----- Original Message ----- From: Hugh Danaher <hdanaher@earthlink.net> Newsgroups: php.general To: Php-General <php-general@lists.php.net> Sent: Tuesday, August 21, 2001 1:16 AM Subject: if statement and imageline() help, I am trying to set up a .jpg file to graph the earnings per year of a company. I can generate a log-normal graph, can get it to display the earnings per year as circles on the graph, but I can't get the " if () " statement to work. I know I am setting two of the variables in the if statement after the if statement executes once, but these variables won't be used until after the " for () " loops once, and therefore should be available for use in " imageline() " on the second loop (where $year>$startyear). Somehow, I think my logic is correct but it mustn't be so. $startyear=1996; $chart_start_year=1992; for ($year=$startyear;$year<=$startyear+7;$year++) { $x=(($year-$chart_start_year)*20)+20; $y=420-log(${"earnings_".$year})*75; if ($year>$startyear) { imageline($image,$first_x,$first_y,$x,$y,$blue); } $first_x=$x; $first_y=$y; imagettftext($image,9,0,$x_distance-4,$y_distance+3,$blue,$font2,"m"); }