Re: FOPEN For Getting Images From Another Site

It should be possible, but the reason it doesn't work for you is because the "filesize" doesn't work on URLs. Try this: $fcontents = join( '', file( 'http://www.php.net' ) ); That's straight from the manual, and I haven't tried it on images, but it should work. The file() simply places the entire contents of a file into an array separated by new lines. Since it's binary, the join() should piece it back together, I think... There's probably an even better way of doing it. Check out the file system functions in the docs, and you may come across something better. -- Matthew Leverton - matthew@aeroinc.net - http://www.allegro.cc -----Original Message----- From: Jeff Gannaway <webmaster@cactusgraphics.com> To: php-general@lists.php.net <php-general@lists.php.net> Date: Thursday, July 13, 2000 10:27 AM Subject: [PHP] FOPEN For Getting Images From Another Site >I tried this the way I thought it would work without any success. > >I need to copy thousands of images form our suppliers' web site to our >retail web site. They've given us permission to do so, but won't let us do >it any simple way (FTP, sending us a CD ROM or ZIP disk, etc). I'd like to >save a day of headaches by writing a PHp scrip tthat will read the >filenames (which I already know) and save them on my server. I tried using >this method to read them: > ><? >$filename = >"http://www.theirsite.com/graphics/imagename.jpg"; >$fd = fopen ($filename, "r"); >$contents = fread ($fd, filesize ($filename)); > >$x = filesize($filename); >print "x = $x<BR> >$contents"; > >fclose ($fd); >?> > >x (the filesize) came up as null value and it didn't display the contents. > >Am I dreaming, or is this possible? > >Thanks, >Jeff >