RE: [PHP] parse error AFTER end of included file??
| From: | Jaxon | Date: | Tue, 28 Aug 2001 15:47:54 +0000 |
| Subject: | RE: [PHP] parse error AFTER end of included file?? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-64839@lists.php.net to get a copy of this message | ||
doh!
thanks for spotting that Kirk!
cheers,
j
> -----Original Message-----
> From: Johnson, Kirk [mailto:kjohnson@zootweb.com]
> Sent: Tuesday, August 28, 2001 11:49 AM
> To: php-general@lists.php.net
> Subject: RE: [PHP] parse error AFTER end of included file??
>
>
> You need to close off this bit of code with a brace '}':
>
> if (!isset($page_id))
> {
>
> Kirk
>
> > -----Original Message-----
> > From: Jaxon [mailto:jaxon@salamander.net]
> > Sent: Tuesday, August 28, 2001 9:34 AM
> > To: php-general@lists.php.net
> > Subject: [PHP] parse error AFTER end of included file??
> >
> >
> > Hi,
> >
> > Can anyone tell me why I have a parse error here?
> >
> > I'm including this file, which is 16 lines, but the error
> > being thrown by
> > the including page reports a parse error in this file on line 17 ???:
> > <?php
> > if (!isset($page_type))
> > {
> > $page_type = "foo";
> > }
> >
> > if (!isset($page_id))
> > {
> > $sql="select page_id from table where fieldname = $value";
> > $link_id = mysql_connect($host, $usr, $pass) or die
> > (mysql_error());
> > mysql_select_db($database, $link_id); //select
> > database catalog
> > $result = mysql_query ($sql, $link_id) or die (mysql_error());
> > //return result set to php
> > if (!$result) echo "wait - no result set!";
> >
> > $page_id = mysql_result($result, 0, fieldname);
> > ?>
> >
> > cheers,
> > jaxon
>
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