Re: Date formatting in PHP 3.0

Thanks, I knew it was something stupid! However, the $dy = date ("D", $row[0]) doesn't work. "* R&Ze:" <renze@datalink.nl> wrote in message news:20010830183255.E15130@pro-pain.telemediair.nl... > <Original message> > From: Paul McGee <pmcgee@inprise.com> > Date: Thu, Aug 30, 2001 at 12:13:21PM -0400 > Message-ID: <20010830170839.89933.qmail@pb1.pair.com> > Subject: [PHP] Date formatting in PHP 3.0 > > > I'm looping through a MSQL db pulling out the dates where I would like to > > display the date and then the day of the week. The problem is that every > > date returns the same day of the week, Wed. I checked the documentation and > > it doesn't say anything about the expression only being executed once during > > inside the WHILE loop. > > > > I've tried: > > > > $m = substr($row[0],0,4); > > $d = substr($row[0],5,2); > > $y = substr($row[0],8,2); > > $dy = date ("D", mktime(0,0,0,$m,$d,$y)); > > > > and just using the date field > > > > $dy = date ("D", $row[0]); > > > > Any help would be greatly appreciated! > > </Original message> > > <Reply> > > Did you give a look at your own code? > A month consisting of 4 digits? > And a year consisting of 2 digits? > I'd say: > > --- PHP code --- > $y = substr($row[0],0,4); > $m = substr($row[0],5,2); > $d = substr($row[0],8,2); > $dy = date ("D", mktime(0,0,0,$m,$d,$y)); > > and just using the date field > > $dy = date ("D", $row[0]); > --- End of PHP code --- > > </Reply> > > -- > > * R&zE: > > </Reply> > > -- > > * R&zE: > > > -- »»»»»»»»»»»»»»»»»»»»»»»» > -- Renze Munnik > -- DataLink BV > -- > -- E: renze@datalink.nl > -- W: +31 23 5326162 > -- F: +31 23 5322144 > -- M: +31 6 21811143 > -- > -- Stationsplein 82 > -- 2011 LM HAARLEM > -- Netherlands > -- > -- http://www.datalink.nl > -- ««««««««««««««««««««««««