Re: Packing file data into a variable???

header("Content-type: audio/m3u"); # Or something not unlike that... Check what you get for a static m3u file. header("Content-length: " . strlen($buffer)); Those two should do it. If you have problems, check the output from a static file, and add headers until it works... >From a Un*x command prompt, just do this: telnet yourserver.com 80 GET /some/path/to/static.m3u HTTP/1.0 Hit return twice after that last line. If you're on Windoze, you'll need to find a telnet client that will let you send raw commands, which, alas, is not what ships with Windows. You end up with some damn GUI if you try this in a default config from MS-DOS prompt :-( -- WARNING richard@zend.com address is an endangered species -- Use ceo@l-i-e.com Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic.com/volunteer.htm ----- Original Message ----- From: Chris Cocuzzo <cuzo@mediaone.net> Newsgroups: php.general To: <php-general@lists.php.net> Sent: Saturday, September 22, 2001 12:51 PM Subject: [PHP]Packing file data into a variable??? hey- my main goal here is to be able to stream an mp3 through any player that can accept m3u files. My idea was to use the format of an m3u file, which looks like this: #EXTM3U #EXTINF:324,cs-1.mp3 http://www.fplg.net/audio/cs-1.mp3 and pack it into a variable to be sent out using a header command...as such: $buffer = "#EXTM3U\n"; $buffer .= "#EXTINF:-1,cs-1.mp3\n"; $buffer .= http://www.fplg.net/audio/cs-1.mp3; I'm not sure of the exact header command I should use, or rather the format of the command I'd send using the header function, but is this possible or do I need to do this some other way?? chris