RE: [PHP] mysql query for current id-1
| From: | Maxim Maletsky \(PHPBeginner.com\) | Date: | Tue, 02 Oct 2001 04:13:39 +0000 |
| Subject: | RE: [PHP] mysql query for current id-1 | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-69537@lists.php.net to get a copy of this message | ||
What about this:
$sql="select id,agent,host, DATE_FORMAT(time_in, '%M %d, %Y, %l:%i') AS
unixdate from logged_in WHERE userid='$current_user' ORDER BY id DESC
LIMIT 1";
I think this should work for your case.
Maxim Maletsky
www.PHPBeginner.com
-----Original Message-----
From: Jason Dulberg [mailto:jdulberg@nas.net]
Sent: martedì 2 ottobre 2001 6.04
To: php-general@lists.php.net
Subject: [PHP] mysql query for current id-1
This is kindof a weird question so bear with me as I try to explain.
I have a session table that gets updated when a user logs in/out. If
they don't logout, some info is left unchanged. I have a cron script
that takes care of the stray sessions so that's all good. In the
sessions table, there's a field "self_logout" which is Y when they
logout properly and N if the cron script removes their session.
What I'd like to do is when the user logs in next time, a search will be
made to look at that users last login session info. If they didn't log
out properly, a notice will appear.
So theoretically, I need to search for something like:
"users current id -1" or their last time of visit.
Here is the sql query that I have so far. But I think that I need to
remove the "self_logout='N'" because that doesn't show the actual last
result; rather it shows the last result where they didn't properly
logout.
$sql="select id,agent,host, DATE_FORMAT(time_in, '%M %d, %Y, %l:%i') AS
unixdate from logged_in WHERE (self_logout='N') AND
(userid='$current_user') ORDER BY id DESC LIMIT 1,1";
Here is my trimmed down table structure:
CREATE TABLE logged_in (
id tinyint(4) DEFAULT '0' NOT NULL auto_increment,
session varchar(100) DEFAULT '0' NOT NULL,
time_in timestamp(14),
time_out varchar(50) DEFAULT '-' NOT NULL,
self_logout char(1) DEFAULT 'N' NOT NULL,
KEY id (id)
);
Did that make any sense? To sum it all up, I just want to remind people
to click "logout" if they forgot the last time.
Thanks for any suggestions!!
__________________
Jason Dulberg
Extreme MTB
http://extreme.nas.net
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net
For additional commands, e-mail: php-general-help@lists.php.net To
contact the list administrators, e-mail: php-list-admin@lists.php.net