Re: problem about ereg function

You really shouldn't be storing a PHP variable in your database... Too easy for a hacker to get some bad PHP into it. You could mess with http://php.net/eval maybe. -- WARNING richard@zend.com address is an endangered species -- Use ceo@l-i-e.com Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic.com/volunteer.htm ----- Original Message ----- From: Mydata <muyuan11@sian.com> Newsgroups: php.general To: <php-general@lists.php.net> Sent: Sunday, September 30, 2001 3:15 AM Subject: problem about ereg function > hi, > I am using ereg funtion to deal with data submmited by form > detail shown below: > > I am using a form to submit some html code include image path code > In submitted php page, I want to replace image path code in html code > (submitted by last page' form), unfortunately the image path code include > some php variable (eg "imag src ='$phpvaribe'"),I want to use ereg function > to replace image path code by the value I need. but when I use eregi_replace > fuction try to replace it . but browser show me parsing error . I don't know > how to use eregi_replace() when php varible in string which needed to be > replaced. Could someone help me. My error code show below: > > MY ERROR CODE: > > eregi_replace("^\"(.)*{$img1_name}\"$","$replacestring",$content) > > > remark:the $img1_name is the php variable in the string which needed to be > replaced > >