REPLACE problem

Hi, i need help with a, seemingly, simple problem... I have a form that is supposed to update a MySql table with only two fields (id and show_id). I use show_id to determine what is showing on my first page and never store more than one value in the table. Now - i cant seem to get the REPLACE to work. First it only added more rows in the table with a new value each time. I solved that by inserting I inserted a hidden value into the form to make sure that the correct (and only) value will be replaced: <input type="hidden" name="fid" value="1"> But, that´s when it stopped working. Show_id is determined by radio buttons in the form and that part is working. In the actual query i REPLACE the value of show_id: $query = "REPLACE INTO puff"; $query .= "(id, show_id)"; $query .= " values('$fid''$show_id')"; I am sure it´s a simple solution. But please point it out for me. Regards # Daniel Alsén | www.mindbash.com # # d@mindbash.com | +46 704 86 14 92 # # ICQ: 63006462 | #