RE: [PHP] Problem when displaying the $ character

It is the same thing. trim() is enough to make it work. Maxim Maletsky www.PHPBeginner.com -----Original Message----- From: Mauricio T?llez Jim?nez [mailto:mtellez@speedy.coacade.uv.mx] On Behalf Of EDUMEXICO Sent: mercoledì 3 ottobre 2001 19.53 To: Dominik Cc: php-general@lists.php.net Subject: Re: [PHP] Problem when displaying the $ character Hi, try this: <? echo " <select name=\"menu\"> <option value=\"$item1\">Item 1</option> <option value=\"$item2\">Item 2</option> </select>"; ?> I hope this can help you. Cheers On Wed, Oct 03, 2001 at 11:08:27AM -0700, Dominik wrote: > Through php, I run a function that creates a list of items in a select > menu as follows: > > <select name="menu"> > <option value="<? echo "$item1"; ?>">Item 1</option> > <option value="<? echo "$item2"; ?>">Item 2</option> > </select> > > but here is how the source code looks: > > <select name="menu"> > <option value=" > item1">Item 1</option> > <option value=" > item2">Item 2</option> > </select> > > It looks like php takes the $ character and inserts a return for it. > This though disrupts the value of the form element. Is there anyway > to make this code appear like it should (with the option tag all on > one line instead of 2)? > > Thanks! > Dominik > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net -- Mauricio Téllez Jiménez Seguimiento Técnico EDUMEXICO edumexico@speedy.coacade.uv.mx edumexico@speedy.uv.mx edumexico@terra.com.mx Zamora No. 25, Col. Centro C.P. 91000, Xalapa, Ver. Tel. 52(28)17-86-87, 17-73-80 Fax. 52(28)18-64-13