Re: Making a string from an Array
| From: | Jim Lucas | Date: | Thu, 25 Oct 2001 19:45:23 +0000 |
| Subject: | Re: Making a string from an Array | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-72334@lists.php.net to get a copy of this message | ||
try this out
$words = explode(" ", $keywordText);
$compare = array('on', 'the', 'in', 'at', 'is',
'it');
foreach ($words AS $value)
{
if (in_array($value, $compare))
{
$ignored[] = $value;
} else {
$included[] = $value;
}
}
Jim Lucas
----- Original Message -----
From: "Sam" <Sam@dragoman.co.uk>
To: "'php'" <php-general@lists.php.net>
Sent: Thursday, October 25, 2001 8:17 AM
Subject: [PHP] Making a string from an Array
> Hi all,
> this may be an easy question, but I'm stuck...
>
> how can this,
>
> $words = explode(" ", $keywordText);
>
> for ( $i = 0; $i < count( $words ); $i++ )
> {
> if ($words[$i]=="on" OR $words[$i]=="the" OR $words[$i]=="in"
> OR$words[$i]=="at" OR $words[$i]=="is" OR $words[$i]=="it")
> {
> $ignored[] = $words[$i];
> }
> else
> {
> $included[] = $words[$i];
> }
> }
>
> How can I make $included and $ignored a string instead of an array.
>
> Thanks
> Sam Rose
>
> p.s. Also I'm only on the digest, so if you could reply directly to me as
> well, that would be a bonus.
>