Re: how to recognize local or server execution?

use $GLOBALS[SERVER_ADDR] it will return the IP address of the server. then use that in an if..then..else Jim ----- Original Message ----- From: "John A. Grant" <jazrant@zsc.nrcan.zc.ca> To: <php-general@lists.php.net> Sent: Friday, October 26, 2001 2:18 PM Subject: [PHP] how to recognize local or server execution? > I have an xxx.php page that runs on my Unix server. I also > run php.exe on my NT box to generate the corresponding > xxx.html file like this: > c:\> php -q xxx.php > xxx.html > > The xxx.php file contains stuff like this: > print "hello\n"; > > That means stdout from the server and the xxx.html file > both contain \n. I would like the xxx.html file to contain > \r\n so it can be viewed/edited with notepad. Yes, > notepad and \r\n both suck, but that's another story... > > So I guess I would like my code to look like this: > if(running php.exe on my NT box){ > $delimiter="\r\n"; > }else{ > $delimiter="\n"; > } > > and then my code looks like: > print "hello$delimiter"; > > How can I do this? > > -- > John A. Grant * I speak only for myself * (remove 'z' to reply) > Radiation Geophysics, Geological Survey of Canada, Ottawa > If you followup, please do NOT e-mail me a copy: I will read it here > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > >