Re: switch-statement overrides use of global arrays?

Hey- I would think you would need to define $array_test outside in a "global" environment rather then inside the function since I think/thought it will just stay scoped in there and that "global" was used to access variables which weren't defined inside a functions scope and make it look outside. In other words //Define GLOBAL $array_test = array(); switch(){ BLAH BLAH } function main() { global $array_test; BLAH BLAH } function test_one(){ global $array_test; BLAH BLAH } Hope that helps. Henrik On Sunday 28 October 2001 15:17, Imar de Vries wrote: > Hi all, > > a very frustrating problem. For some reason I am not able to pass on an > array between two functions, although I declare it global in both of > them. I suspect my use of a switch statement to control the flow of the > functions is causing some trouble, but I'm not sure. Changing the order > in which I declare the array global did not help, nor the use of > $GLOBALS. > > This is a simple representation of what I do: > > switch ($action) { > default: > main(); > break; > case "test_one": > test_one(); > break; > } > > // ------------------------------------------- > > function main() { > > $array_test = array(); > global $array_test; > > $array_test[0] = "First array, first element"; > $array_test[1] = "First array, second element"; > > print("Content of first array in the main function is now:<br>"); > var_dump($array_test); > > print ("<p><form method=\"post\" action=\"arraytest.php\" > enctype=\"multipart/form-data\">"); > ?> > <input type="hidden" name="action" value="test_one"> > <input type="submit" value="Test" tabindex="6"> > </form> > <? > } > > // ------------------------------------------- > > function test_one() { > > global $array_test; > > // This results in NULL > > print("Content of first array in the first test function is now:<br>"); > > var_dump($array_test); > > $array_test[2] = "First array, third element"; > $array_test[3] = "First array, fourth element"; > > // This results in the third and fourth element being shown > > print("<p>After addition, content of first array is:<br>"); > var_dump($array_test); > } -- Henrik Hudson lists@rhavenn.net