Re: @#$@# Reg Expressions

From: Date: Tue, 30 Oct 2001 03:09:21 +0000
Subject: Re: @#$@# Reg Expressions
References: 1 2  Groups: php.general 
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martin, jack .. cheers for the replies Jack.. I am trying to strip out all links in the page that is between the <a href and </a> I was using $html =GETSITE($url); $the_array=spliti("<A (.*)</A>", $html,-1); //spliti to avoid any case sensitivity. foreach($the_array AS $k) echo $k."<HR>"; I had given preg_split a go but just got flummoxed with the need to slash everything .. Martin .. I'd tried that .. but i get an array count of 0 from $the_array ..(from $the_array=split("<A ([^>]*)</A>", $html,-1); echo count($the_array); Jack Dempsey wrote:
ok, are you trying to get the links returned or just split on them? i missed your original post. watch your caps as well... i'd use preg_split also jack -----Original Message----- From: brendan [mailto:brendan.gogarty@utas.edu.au] Sent: Monday, October 29, 2001 9:59 PM To: php-general@lists.php.net Subject: [PHP] @#$@# Reg Expressions thanks but it didnt work either .. ;) Matt Friedman wrote:
Try putting a "?" after your quantifier for "non-greedy" matching. Something like: $the_array=split("<A (.*?)</A>", $html,-1); Matt. ----- Original Message ----- From: "brendan" <brendan.gogarty@utas.edu.au> To: <php-general@lists.php.net> Sent: Monday, October 29, 2001 7:55 PM Subject: [PHP] @#$@# Reg Expressions
love em.. right now I hate em.. can someone inform me why the below doesnt work? it is intended to strip out all the links in a page and return an array .. insanity is just starting to set in.. cheers $html =GETSITE($url); // and put in a new line break behind every anchor tag $the_array=spliti("<A (.*)</A>", $html,-1); echo $the_array ; foreach($the_array AS $k) echo $k."<HR>"; } -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net
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