Re: Strange class behavior

Hi - Take a closer look at the examples in http://www.php.net/manual/language.oop.php Loose the second '$' in your class variable references - ie: $this->id = $theId; $this->name = $theName; echo "Node id is: " . $n->id; The way you had it originally, it worked sorta like variable variables; in your echo statement, for example, it first looked for the value of '$id' in your main program (_not_ in the class definition). If $id was set to 'gleep', your echo statement would be equivalent to echo "Node id is: " . $n->gleep; If perchance $id was set to 'id', the statement would actually have worked. -steve At 11:32 AM -0400 7/19/00, Harsanyi Alexandru wrote:

Hi, I'm relatively new to PHP and I got stuck at using classes and objects in PHP. Here is an example: --------------------- <html> <head></head> <body> <?php class node { var $id, $name; function node($theId, $theName) { $this->$id = $theId; $this->$name = $theName; } } $n = new node(1, "some_node"); echo "Node id is: " . $n->$id; ?> </body> </html> -------------------------- A class is declared with an $id and a $name members. The constructor initializes them. However, when I run the script, I get the following ansver: Node id is: some_node although I referenced $n->$id, which was initialized in the constructor to 1. What am I missing here? BTW, what does the "var" keyword do? If I remove the "var" line I don't notice any difference.... Best Regards, Alex.

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| Steve Edberg                           University of California, Davis |
| sbedberg@ucdavis.edu                               Computer Consultant |
| http://aesric.ucdavis.edu/                   http://pgfsun.ucdavis.edu |

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