Re: using PHP script to add address'es of all picture files in a dir to MYSQL DB
| From: | Stefan Rusterholz | Date: | Tue, 06 Nov 2001 14:06:27 +0000 |
| Subject: | Re: using PHP script to add address'es of all picture files in a dir to MYSQL DB | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-73599@lists.php.net to get a copy of this message | ||
Yes.
I'm sorry, my fault.
getDircon was my old name for that function (don't ask me what it stands
for - I just can't remember =) I think it was something like Dircon =
Directory Content - but I'm not sure)
Replace every getDircon with the new name "getFilesInDir". It then should
work.
Good luck
Stefan Rusterholz, s.rusterholz@interaktion.ch
From: "Daniel" <spam@nospam.com>
To: <php-general@lists.php.net>
Sent: Tuesday, November 06, 2001 3:01 PM
Subject: Re: [PHP] using PHP script to add address'es of all picture files
in a dir to MYSQL DB
> I am running on *nix apache server (acording to status.php, apache
document
> root in status.php is /home/sites/site158/web
> ) so I change code as follows:
>
> <?php
> function getFilesInDir($theDir, $ignore=true){
> $delim = "/";
> $dircon = array();
> $dh = openDir($theDir);
> while ($dirORfile = readdir($dh)){
> if ($ignore == false || ($dirORfile != '.' && $dirORfile !=
> '..')){
> if (is_Dir($theDir.$delim.$dirORfile)){
> #echo "DIR: $theDir$delim$dirORfile\n";
> $files = array();
> $files = getDircon($theDir.$delim.$dirORfile); // error on this
line
> $dircon = array_merge($dircon,$files);
> }else{
> #echo "FILE: $theDir$delim$dirORfile\n";
> array_push($dircon,$theDir.$delim.$dirORfile);
> }
> }
> }
>
> return $dircon;
> }
>
> $basedir = "/home/sites/site158/web"; // document root in status.php is
> /home/sites/site158/web
> $dircon = getFilesInDir($basedir);
> foreach ($dircon as $file){
> echo "$file\n";
> }
>
> ?>
>
> I get a error message:
>
> Fatal error: Call to undefined function: getdircon() in
> /home/sites/site158/web/DUCU-pages/files.php on line 18
>
> Any ideas why?
>
> Daniel
>
> "Stefan Rusterholz" <scripting@interaktion.ch> wrote in message
> news:004201c166bf$c92ada20$3c01a8c0@quasimodo...
> > I appended a function which gives you all files in a directory
(including
> > subdirectories). I wrote it in a hurry for something else so don't
expect
> > very good code.
> > You just set the $basedir to that directory where your .jpg's are in.
Then
> > you do a 'foreach ($files as $file)' loop and check each file if it is a
> jpg
> > (if it is ok for you then I'd suggest to use a preg_match like
> "\\.jpg$/i")
> > and then do the UPDATE or INSERT query. That's it.
> > Just one point to clear: it is written for windows, so directories are
> > delimited by backslash (\) and not by slash (/). If you want to use it
on
> a
> > *nix-box you will have to search an replace all \\.
> >
> > Code (just paste it into a .php file an look how it works)
> > <?php
> > function getFilesInDir($theDir, $ignore=true){
> > $delim = "\\";
> > $dircon = array();
> > $dh = openDir($theDir);
> > while ($dirORfile = readdir($dh)){
> > if ($ignore == false || ($dirORfile != '.' && $dirORfile !=
> > '..')){
> > if (is_Dir($theDir.$delim.$dirORfile)){
> > #echo "DIR: $theDir$delim$dirORfile\n";
> > $files = array();
> > $files = getDircon($theDir.$delim.$dirORfile);
> > $dircon = array_merge($dircon,$files);
> > }else{
> > #echo "FILE: $theDir$delim$dirORfile\n";
> > array_push($dircon,$theDir.$delim.$dirORfile);
> > }
> > }
> > }
> >
> > return $dircon;
> > }
> >
> > $basedir = "C:\Your Image Directory";
> > $dircon = getFilesInDir($basedir);
> > foreach ($dircon as $file){
> > echo "$file\n";
> > }
> >
> > ?>
> > Stefan Rusterholz, s.rusterholz@interaktion.ch
> > ----------------------------------
> > interaktion gmbh
> > Stefan Rusterholz
> > Zürichbergstrasse 17
> > 8032 Zürich
> > ----------------------------------
> > T. +41 1 253 19 55
> > F. +41 1 253 19 56
> > W3 www.interaktion.ch
> > ----------------------------------
> > ----- Original Message -----
> > From: "Daniel" <spam@nospam.com>
> > To: <php-general@lists.php.net>
> > Sent: Tuesday, November 06, 2001 1:12 PM
> > Subject: [PHP] using PHP script to add address'es of all picture files
in
> a
> > dir to MYSQL DB
> >
> >
> > > Hi,
> > >
> > > I want to make a simple database driven photo gallery for my site
where
> > > users can search the picture descriptions to find the pictures they
> want,
> > > all fairly simple PHP/MySQL stuff which I know. My big problem is
that
> I
> > > have like 500+ images I want to put into the MySQL DB and I am way too
> > lazy
> > > to consider doing it the hard way. I was wondering if it would be
> > possible
> > > to write a PHP script which would get a list of all the .jpg files in
> its
> > > current directory and then insert a reference for each file (basically
> > just
> > > its location on the web server) into the MySQL PHOTO table? I was
> > thinking
> > > about this on the train yesterday so heres the pseudo PHP/C code of
the
> > sort
> > > of script I was thinking about(I don't know the PHP file functions):
> > >
> > > file://get the number of jpeg files in same dir as this script (I
don't
> > know code
> > > for this)
> > > $NumFiles = GetNumberOfJPGFilesInDirectory();
> > > While ($NumFiles > 0)
> > > {
> > > file://get file location of current jpeg file (I don't know code
for
> > this)
> > > $FileName = GetFileNameAndLocation($NumFiles);
> > > // construct MySQL query
> > > $sql = "INSERT INTO PHOTO SET " . "FILE='$FileName ";
> > > file://add file location of current jpeg and do error handling
(easy
> > stuff)
> > > if (mysql_query($sql))
> > > {
> > > echo("Photo " . $FileName ." has been
> > > added.<br>");
> > > }else
> > > {
> > > echo("Error adding photo: " . mysql_error() . "
> > > <br>");
> > > }
> > > $NumFiles = $NumFiles-1;
> > > }
> > >
> > > Would anyone be able to help me get the code for this script right? I
> can
> > > do basic PHP & MySQL stuff but I am not familiar with PHP file
functions
> > so
> > > I need someone to help me get it working...
> > >
> > >
> > > Cheers,
> > >
> > > Daniel
> > >
> > >
> > >
> > >
> > >
> > > --
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> > >
> > >
> >
>
>
>
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