Re: Re: form javascript and php error

From: Date: Thu, 08 Nov 2001 10:11:33 +0000
Subject: Re: Re: form javascript and php error
References: 1 2  Groups: php.general 
Request: Send a blank email to php-general+get-73854@lists.php.net to get a copy of this message
Hi, It works, tnx! ----- Original Message ----- From: "dav" <dav@thecloud.o> To: <php-general@lists.php.net> Sent: Thursday, November 08, 2001 8:49 AM Subject: [PHP] Re: form javascript and php error > I think this is your client/server discussion: > 1) When you click load an image called test.php > one clicks > 2) Load the test.php > 3) SERVER tells client: What is coming now it's an image (it's the header) > 4) SERVER sends to client a REDIRECTION (not an image) > 5) The client says: Hey, you should have sent an image, not a redirectio, > result: image broken. > > SOLUTION: > Showpic function should fopen the remote image and copy byte-to-byte it to > the output so that the client receive image data and not a redirection to an > image > > > "Bas Jobsen" <bas@startpunt.cc> ha scritto nel messaggio > news:002901c167f6$a89f1c20$9600000a@lan... > > Hello, > > > > I have got this php file: > > -- > > <form method='post'> > > <input type='submit' value='SEND'> > > </form> > > <script type="text/javascript" language="JavaScript"> > > <!-- > > d=document; > > d.write("<img src='test.php'>"); > > </script> > > -- > > and test.php: > > -- > > <? > > function showpic() > > { > > header ("location: > > http://www.linkotheek.nl/images/logo.gif"); > > exit; > > } > > showpic(); > > exit; > > ?> > > -- > > > > pressing the submit button will give my a broken image. > > > > I don't understand why? > > > > Thanks, > > > > Bas > > > > > > > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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