RE: [PHP] Supplied argument is not a valid MySQL result resource

From: Date: Thu, 08 Nov 2001 15:38:49 +0000
Subject: RE: [PHP] Supplied argument is not a valid MySQL result resource
References: 1  Groups: php.general 
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> $gi = "Y"; > $sqlf = "SELECT * FROM products WHERE collection_id = $id AND > group_image = $gi ORDER BY > sort_order ASC"; > $resultf = mysql_query($sqlf); > while ($group_images = mysql_fetch_array($resultf)) { > $list_images .= "<a > href=test3.php?id=".$group_images["prod_id"]."><img > src=\"images/product/".$group_images["product_image"]."\" > border=\"0\" > > alt=\"".$group_images["product_name"]."\"></a><br>"; > } Hi Presumably you already connected to the db? Try putting quotes around your variables in the query M:

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