Re: variable issue
| From: | R'twick Niceorgaw | Date: | Fri, 09 Nov 2001 19:39:27 +0000 |
| Subject: | Re: variable issue | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-74046@lists.php.net to get a copy of this message | ||
replace the if statement if(!$dte)
with
if (!isset($dte))
----- Original Message -----
From: "Johnson, Kirk" <kjohnson@zootweb.com>
To: "PHP General" <php-general@lists.php.net>
Sent: Friday, November 09, 2001 2:35 PM
Subject: RE: [PHP] variable issue
> The else clause can be removed, since it is not doing anything. What is
the
> error message?
>
> Kirk
>
> > Hey everyone, I need some help with a variable issue. How can
> > I delcare a variable and then if a url variable of the same
> > name is present use that value instead?
> >
> > this is what I have:
> > if(!$dte)
> > {
> > $dte=date("j", time()+$ctime);
> > }
> > else
> > {
> > $dte=$dte;
> > }
> > and this causing an error in the 'if' expression.
>
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