take date and convert to day of year
| From: | sundogcurt | Date: | Tue, 13 Nov 2001 20:56:31 +0000 |
| Subject: | take date and convert to day of year | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-74491@lists.php.net to get a copy of this message | ||
Hi guys, I know that you can take todays date and display it as the numeric day of the year, 1 - 365 / 0 - 364 etc.
But can you take a date such as (November-30-1971) and convert that to the numeric day of the year?
I have been trying to do this but have had no joy, I don't think my code is even close.
$dob = getdate("Nov-30-1971");
$dobnum = $dob['yday'];
print $dobnum;
$dob 'should' be an array and 'yday' should be the numeric value for the day of the year, right?!?
This is what I am trying, and how I understand it, using 'yday' should give you basically the same output as date ("z");
What I would like is the ability to convert any date to the days numeric value. Any help would be GREATLY appreciated.
(C: