Re: take date and convert to day of year

From: Date: Wed, 14 Nov 2001 01:13:39 +0000
Subject: Re: take date and convert to day of year
References: 1  Groups: php.general 
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I have tried to implement your code Martin, and I do thank you VERY MUCH for the help, but your code seems to have the same trouble as mine, it doesn't matter what date I start with, I end up with 364 as the day of the year, I am on win32 though I don't know if that matters. Here is what I tried: //FORMAT HAS TO BE date("d-M-Y"); //GET DAY OF YEAR FOR DOB utime = UNIX time $utine = strtotime("30-Nov-1971"); $dob = getdate($utime); $dobnum = $dob['yday']; print "dob is " . $dobnum . "<br>"; //GET DAY OF YEAR FOR TODAY //$today = date("d-M-Y"); $utoday = strtotime(date("d-M-Y")); $today = getdate($utoday); $todaynum = $today['yday']; print "today is " . $todaynum . "<br>"; There should be a different of about 17 days here right? Not if this is returning 364 for $dobnum, then it's 48! martin.towell@world.net wrote:
looking at the manual, getdate() is meant to be passed a unix time stamp, so, you'll need to use strtotime() first thus: $utime = strtotime("30-Nov-1971"); $dob = getdate($utime); $dobnum = $dob['yday']; print $dobnum; Notice I changed the format of the date, when I tried using the original format, strtotime() complained, saying it couldn't convert it. Martin T -----Original Message----- From: sundogcurt [mailto:sundogcurt@netscape.net] Sent: Wednesday, November 14, 2001 7:57 AM To: GENERAL PHP LIST Subject: [PHP] take date and convert to day of year Hi guys, I know that you can take todays date and display it as the numeric day of the year, 1 - 365 / 0 - 364 etc. But can you take a date such as (November-30-1971) and convert that to the numeric day of the year? I have been trying to do this but have had no joy, I don't think my code is even close. $dob = getdate("Nov-30-1971"); $dobnum = $dob['yday']; print $dobnum; $dob 'should' be an array and 'yday' should be the numeric value for the day of the year, right?!? This is what I am trying, and how I understand it, using 'yday' should give you basically the same output as date ("z"); What I would like is the ability to convert any date to the days numeric value. Any help would be GREATLY appreciated. (C:


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