Re: passing parameters to functions

""T.R. Henigson"" <ted@3bits.com> wrote in message news:006f01bff26e$bda11c80$02fea8c0@u3... > I have a function which has four parameters. I can pass variables > to each of the four parameters by calling the function > > Example($parameter1=0,$parameter2=0,$parameter3=0,$parameter4=0); > > But if I assign the variable $temp, the concatenated string of > the four parameters delimited with commas and then call the function > as follows > > > $temp=$parameter1.",".$parameter2.",".$parameter3.",".$parameter4; > Example($temp); > > It ends up considering $temp as $parameter1 in the function, and then > using default values for the other three parameters. How do I get the > comma-delimited string to map to all four parameters? Can't. Use an array, or use explode inside Example() and pass only one parameter. > > Ted Henigson > > > Bonus question: In quoting strings, if I don't have to do any variable > interpolation, does it matter whether I use single or double quotes? I believe (and I could be wrong) that in some languages (C/C++, for example) 'X' encloses a single byte, while "" encloses strings of bytes. In PHP, there seems to be no difference. IMHO, it's better to standardize on that. You save little effort by doing ' instead of shift + '. -- O.