RE: [PHP] Directory Contents Listing

From: Date: Wed, 28 Nov 2001 11:38:25 +0000
Subject: RE: [PHP] Directory Contents Listing
Groups: php.general 
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Here's an example code I use <? // print the current directory in unordered list print("<UL>\n"); // get each entry within the directory & return to user with the link $myDirectory = dir("."); while($entryName = $myDirectory->read()) { if ($entryName != "." && $entryName != ".." && $entryName != "index.php"){ print("<LI><a href=$entryName>$entryName \n</a>"); } } ?> Hope it helps! -----Original Message----- From: Steve Werby [mailto:steve-lists@befriend.com] Sent: 28 November 2001 05:39 To: Deependra B. Tandukar; php-general@lists.php.net Subject: Re: [PHP] Directory Contents Listing "Deependra B. Tandukar" <deepndra@icimod.org.np> wrote: > How do I display the directory contents using PHP? See readdir() in the online manual. I'm pretty sure it even has example code you could paste in. -- Steve Werby President, Befriend Internet Services LLC http://www.befriend.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net

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