Re: fsockopen() prob

Global variables are not really global in php because they are not available from within functions unless you specifically declare them as global. This should work: 130 function get_line { 131 global $socket_open; 132 $buffer = fgets($socket_open,500); 133 $buffer = eregi_replace("(\r|\n)","",$buffer); 134 return $buffer; 135 } Fred Yura <bodybuilders@comic.com> wrote in message news:3C054EE3.19234.2726172@localhost... > I have a global variable > $socket_open = fsockopen($pop_server, 110, $errno, $errstr, 60 ); > then I define the function: > > 130 function get_line { > 131 $buffer = fgets($socket_open,500); > 132 $buffer = eregi_replace("(\r|\n)","",$buffer); > 133 return $buffer; > 134 } > > Here I've got the prob - it doesn't work, it sais: Warning: Supplied argument is not a valid File- > Handle resource in .../inc/pop-functions.inc on line 131 > > At the same time $socket_open returns "Resource id #2" I don't know what it means, could > anyone help me with it? > > Youri > > > > > <>< <>< <>< <>< God is our provider ><> > ><> ><> ><> > http://www.body-builders.org > >