Re: database conection (newby)

You've got too many parameters in the mysql_connect() and mysql_select_db() functions. You don't need the %s stuff. Here's what it should be: $conn = mysql_connect($connectie,$uid,$pwd); mysql_select_db($database,$conn); Good luck, Tyler Longren Captain Jack Communications tyler@captainjack.com www.captainjack.com ----- Original Message ----- From: "Tommy Straetemans" <tommy@infoweb.be> To: <php-general@lists.php.net> Sent: Thursday, November 29, 2001 8:52 AM Subject: [PHP] database conection (newby) > Hi > > I'am totaly new in php i work always with asp. > I give the folowing hidden fields to a php script > <input type=hidden name=connectie value="mysqlhost.mijndomein.be:3306"> > <input type=hidden name=uid value="U0498526"> > <input type=hidden name=pwd value="iwinfo59"> > <input type=hidden name=database value="D0498526"> > > and in my php script i try to make my connection as follows: > > $conn = mysql_connect('%s','%s','%s',$connectie,$uid,$pwd); > mysql_select_db('%s',$database,$conn); > > but i keep getting this error: > Warning: Wrong parameter count for mysql_connect() in > /home/users/mijndomein.be/admin/x.php on line 27 > > What do i wrong or is there a method to make my connection with a include > file? > > > > > Tommy Straetemans > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >