Re: problems with looping array
| From: | Fred | Date: | Mon, 03 Dec 2001 09:03:37 +0000 |
| Subject: | Re: problems with looping array | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-76368@lists.php.net to get a copy of this message | ||
Strings in your sql query must be quoted. Try this instead:
> $result = mysql_query("SELECT * FROM ar
> LEFT JOIN company on ar.company_id=company.company_id
> LEFT JOIN scale on ar.scale_id=scale.scale_id
> WHERE item_number = \"$item[$index]\")";
Fred
Jordan <newimagedesign@newimagedesign.com> wrote in message
news:20011203081812.81073.qmail@pb1.pair.com...
> here's the situation. I'm making a shopping cart, when an item is added
> it's item number is added into an array. I then want this array's items
to
> be compared agains the database. Unfortunately I haven't been able to use
a
> variable in the query string of MySQL. something along the lines of....
>
>
> <?PHP
>
> include ('connect.php');
>
> $result = mysql_query("SELECT * FROM ar
> LEFT JOIN company on ar.company_id=company.company_id
> LEFT JOIN scale on ar.scale_id=scale.scale_id
> WHERE item_number =" . $item[$index]);
>
> ?>
>
> where $item is the array of item numbers and $index is an auto
incrementing
> number that increments at the end of the loop. Please help if you know of
> anyway to use this variable. Also, I can post my whole script if
needed...I
> just didn't want unneeded info posted. Thanks in advance.
>
> -Jordan
>
>