Re: Function definition: how to make default argument an empty array?
| From: | Michael Sims | Date: | Sat, 22 Dec 2001 20:27:42 +0000 |
| Subject: | Re: Function definition: how to make default argument an empty array? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-78589@lists.php.net to get a copy of this message | ||
At 01:17 PM 12/22/2001 +0100, Michael Jurgens wrote:
I'm now looking for a way to have the second (optional) argument be an array of strings. I can't get it to work though... In pseudo-code: function makeyogurt ($flavour, $type = 'EMPTY ARRAY') { }Does this work? function makeyogurt ($flavour, $type = "") {
$type = (array) $type;
...} or function makeyogurt ($flavour, $type = "") {
settype ($type, "array");
...} ??