Re: Re: Generate Alphabet

"Bogdan Stancescu" <mgv@fx.ro> wrote in message news:3C2C787D.602B807@fx.ro... > 2. print $letter++ -- why doesn't this evaluate to "b" at the first loop when > it's already 'a'? Ok, this I may be able to explain because it's neither "print > ++$letter" nor "print ($letter++)", but I wouldn't have trusted this syntax to > work this way a million years! > $foo++ is 'postfix', ++$foo is 'prefix' This means that the addition of 1 occurs AFTER (hence post) the expression's value is returned, not before. In other words, it's equivalent to this: print $foo; $foo = $foo + 1; not this: $foo = $foo + 1; print $foo; -- Daniel Grace