Re: how can I add a variable to this sample

$service_type_insert = $x[${key}service_type]; should work. On Thu, 3 Jan 2002, Tom Beidler wrote: > I have a large form that I would like to edit a number of records. I'm > putting all of the fields into one array and then I would like to pull the > fields independently from a loop. > > > Here's part of the loop > > foreach ($z as $key => $value) { > $service_type_insert = $x['$keyservice_type']; > > What I'm looking for is for the $key variable to be replaced with the record > id, which is what $key is. So the second line should look like; > > $service_type_insert = $x['629service_type']; > > I've tried a number of variations, i.e.; > > $service_type_insert = $x[$keyservice_type]; > > $service_type_insert = $x['\$keyservice_type']; > > $service_type_insert = $x["$keyservice_type"]; > > Is there a way that I can format it correctly? > > Thanks, > Tom > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >