SV: [PHP] Re: Still need help with miscount

From: Date: Sat, 05 Jan 2002 13:01:11 +0000
Subject: SV: [PHP] Re: Still need help with miscount
References: 1  Groups: php.general 
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I have worked this over in my head over the holidays and still haven´t got a solution. Can anyone help? I have a MySql table populated with numerical values from 0 to 10 in five different fields. I need a function that counts all occurances of each value, ie: 1: 12, 2: 3, 4: 74 etc... I have worked with this code: $num_vals = array (); for ($i=0; $i<10; $i++) { $shot_count = "SELECT COUNT(*) FROM statistik WHERE shooter='$shooter_login' AND ((shot_one = '$i') OR (shot_two = '$i') OR (shot_three = '$i') OR (shot_four = '$i') OR (shot_five = '$i'))"; $result = mysql_query($shot_count); $num_vals[$i] = mysql_fetch_array($result); } The code works...but returns the wrong results. If i count from the database manually there is always some occurances missing. So, today i tried to count the values from an array instead: $shotcount = "SELECT shot_one, shot_two, shot_three, shot_four, shot_five FROM statistik WHERE shooter='$shooter_login'"; $results = mysql_query($shotcount); $bam = mysql_fetch_array($results); $count = array_count_values ($bam); while (list($key,$value) = each($count)) { echo "$key : $value<br>"; } But this works even worse...it seems to stop populating the array (or counting the values) after only a couple of rows from the db. The result looks like: 3 : 4 5 : 2 7 : 2 9 : 2 And there should be alot more of those keys...and a couple of keys more as well... I would appreciate any help on this guys. I am soooo stuck :( # Daniel Alsén | www.mindbash.com # # d@mindbash.com | +46 704 86 14 92 # # ICQ: 63006462 | +46 8 694 82 22 # # PGP: http://www.mindbash.com/pgp/ #

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