Re: does this work?

I tried that... I get the same error (same line and everything). As a side note, I haven't ever had to quote the first argument in mysql_query() before... This is quite a conundrum, eh? Erik On Friday, January 11, 2002, at 04:25 AM, Kevin Stone wrote:

Hmm I believe that the mysql_query() function requires quotes around the query statement even it it is being passed as a variable.. mysql_query("$tempsql", $db); -Kevin

It seems that I have a "parse error" somewhere in the following code (since that's the only code in my script, it's a test script): // arraytest.php $tempsql = "SELECT COUNT(*) AS count FROM divisions"; $tempresult = mysql_query($tempsql, $db); $temprow = mysql_fetch_array($tempresult); echo $temprow["count"]; Yet, it works fine in the mysql client. Thus, I am led to believe that PHP is not capable of constructing the same kinds of SQL statements that can be constructed in the mysql client. Is this the case? Erik PS: what I am -really- trying to do is dynamically fill in a <select> listbox with <options> that correspond to all of the records in a given table. Like so: <form>

      <select>
           <?php
           foreach

($record_id_and_record_name_pair_pulled_from_mysql_query) {

               print("<option

value=\"${record_id}\">${record_name}</option>");

           }
           ?>
       </select>

</form> but I am unsure of how to grab multiple values from the mysql_query() and load them into an array. Has anyone done this before? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list- admin@lists.php.net